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I used my new test leads to test an iP4000 power supply unit (PSU). This PSU is marked with the output voltages 24 V DC and 27 V DC. The output connector has 5 pins, and starting with the yellow control input wire and naming it "1", "2" is white and ground, "3" is blue and +27 V, "4" is black and ground and "5" is red and +24 V.
With the PSU connected to the mains and no voltage applied to pin 1 the stand by voltages are pin 3 = +9.6 V and pin 5 = +7.8 V.
With the PSU connected to the mains and +3.2 V from a Lithium coin cell applied to pin 1 and -3.2 V from the cell connected to one of the ground pins the operating voltages are pin 3 = +27.8 V and pin 5 = 23.8 V.
The behaviour of the iP4000 PSU is very similar to this.
I don't know the iP5000 PSU but if it is OK it should behave in a similar manner. Start in stand by mode and locate the 3 (?) voltage outputs, then the "left over" pin should be the control input. Applying approximately 3 V to this pin should shift the PSU into operating mode. I'm guessing about this PSU but I'm more than 80% sure I'm right.
With the PSU connected to the mains and no voltage applied to pin 1 the stand by voltages are pin 3 = +9.6 V and pin 5 = +7.8 V.
With the PSU connected to the mains and +3.2 V from a Lithium coin cell applied to pin 1 and -3.2 V from the cell connected to one of the ground pins the operating voltages are pin 3 = +27.8 V and pin 5 = 23.8 V.
The behaviour of the iP4000 PSU is very similar to this.
I don't know the iP5000 PSU but if it is OK it should behave in a similar manner. Start in stand by mode and locate the 3 (?) voltage outputs, then the "left over" pin should be the control input. Applying approximately 3 V to this pin should shift the PSU into operating mode. I'm guessing about this PSU but I'm more than 80% sure I'm right.
